The eleventh homework had...
The assignment's 36 points were (unevenly) divided among the 11 sections as follows:
| A | B | C | D | E | F | |||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| handout... 28 | 5 | 3 | 2 | 3 | 3 | 8 | ...installment 1 | |||||||
| handout... 29 | 3 | 2 | 4 | 2 | 1 | ...installment 2 | 
You should be able to find the corresponding eleven scores on the front
page of your homework, arranged in a 2-row  quite
 quite
A few comments on specific exercises...
| 29C. | Please note that Rosen's definition of bipartite (def. 5 on
      p. 449) requires the partitions
      V1 and V2 to both
      be nonempty.  This implies that a graph with exactly one vertex
      can never be bipartite, since its unique vertex would have to lie
      either
      in V1
      (in which case  | 
|---|
Our solutions to the eleventh homework have been posted.
For those who are curious, the median score was 33, and the mean score was 31.5 (sigma ~ 4).