Fourth example continued. . .

Strategy: look at the characters of s one by one, starting from the beginning. Return as soon as c is found. Use a variable j to tell how much of s has been �scanned� (looked at).

General picture: c is not in s[0..j-1], i.e. c is not one of the first j characters of s, and 0 <= j <= s.length().

Initialization: j= 0;

When can the loop stop?

When j= s.length() or c = s[j].

So the loop condition is

j != s.length() && s.charAt(j) != c

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