Recitation 5: Folding and tail recursion

Folding

Suppose we want to write a function to sum a list of integers.  By now you should be able to write the following code:

let rec sum (l : int list) : int =
match l with
[] -> 0
| x :: xs -> x + (sum xs)

Now suppose we want to concatenate a list of strings.  We can write:

let rec concat (l : string list) : string =
match l with
[] -> ""
| x :: xs -> x ^ (concat xs)

Notice that both functions look almost identical.  With the exception of the different types and different operation (^ vs +), both functions are equivalent.  In both cases, we walk down a list performing some operation with the data at each step.  Since we love to reuse code in this class, is there some easier way to encode this?

It turns out we can abstract all of the details of traversing a list.  The idea is simple.  As we walk across a list, we store an accumulator, a value that stores some data that is important to us.  For example, if we want to walk across a list of integers and sum them, we could store the current sum in the accumulator.  We start with the accumulator set to 0.  As we come across each new element, we add the element to the accumulator.  When we reach the end, we return the value stored in the accumulator.

Let's try to rewrite the sum function to introduce the idea of an accumulator.

let rec sum' (acc : int) (l : int list) : int =
match l with
[] -> acc
| x :: xs -> sum' (acc + x) xs

Of course, to get the sum, we must call sum' with 0 for the initial acc value.  Similarly, we can rewrite concat with this concept of the accumulator.

let rec concat' (acc : string) (l : string list) : string =
match l with
[] -> acc
| x :: xs -> concat' (acc ^ x) xs

To use this function, we pass in the empty string for the initial accumulator.  Now we see even more similarity between the two functions.  We are in a position to eliminate any differences between the two by passing in the operator that acts on the head of the list and the accumulator.  The result is the most powerful list function in the list library:  List.fold_left.

let rec fold_left (f : 'a -> 'b ->'a) (acc : 'a) (l : 'b list): 'a =
match l with
[] -> acc
| x :: xs -> fold_left f (f acc x) xs

Now we can rewrite sum and concat as

let sum (l : int list) : int =
List.fold_left (fun acc x -> acc + x) 0 l
let concat (l : string list) : string =
List.fold_left (fun acc x -> acc ^ x) "" l

Given a function f of type 'a -> 'b -> 'a, the expression List.fold_left f b [x1; x2; ...; xn] evaluates to f (... (f (f b x1) x2) ...) xn. The 'left' in List.fold_left comes from the fact that it walks the list from left to right.  Thus, we have to be careful sometimes in applying functions in the right order (hence acc ^ x and not x ^ acc in concat above).  There is also a library function List.fold_right which traverses the list from right to left. Note that List.fold_right uses a different argument order than List.fold_left. The list and the accumulator arguments are switched, and the function takes in the accumulator as its second curried argument, not its first. So, List.fold_right f [x1; x2; ...; xn] b evaluates to f x1 (f x2 (... (f xn b)...)). The code for List.fold_right is

let rec fold_right (f : 'a -> 'b -> 'b) (l : 'a list) (acc : 'b) : 'b =
match l with
[] -> acc
| x :: xs -> f x (List.fold_right f xs acc)

We can use List.fold_right to write concat in the more natural manner.

let concat (l : string list) : string =
List.fold_right (fun x acc -> x ^ acc) l ""

But we can still do better.  Remember, both List.fold_left and List.fold_right are curried, so that we can leave out the list argument and write

let sum = List.fold_left (fun a x -> x + a) 0
let concat = List.fold_left (fun a x -> a ^ x) ""

We can do even better.  OCaml provides a convenient notation to use infix binary operators as curried functions by enclosing them in parentheses. So (+) is a curried function that takes two integers and add them, (^) is a curried function that takes two strings and concatenates them.  We can write sum and concat one last time as

let sum = List.fold_left (+) 0
let concat = List.fold_left (^) ""

Now you see the true power of functional programming.  Try rewriting functions that sum a list of ints and concatenate a list of strings in 2 short lines of Java.

Folding is so powerful, that we can write almost every other general list function in terms of List.fold_left or List.fold_right.  For example,

let length l = List.fold_left (fun a _ -> a + 1) 0 l
let rev l = List.fold_left (fun a x -> x :: a) [] l
let map f l = List.fold_right (fun x a -> (f x) :: a) l []
let app f l = List.fold_left (fun _ x -> f x) () l
let filter f l =
List.fold_right (fun x a -> if f x then x :: a else a) l []

When writing code with fold, OCaml's type system can be tremendously helpful.  The type of List.fold_left is ('a -> 'b -> 'a) -> 'a -> 'b list -> 'a.  Suppose we know we are applying List.fold_left to an int list and we want to return a string.  Then 'b is of type int and 'a is of type string.  So right away, we know that the function we have to pass into List.fold_left is of type string -> int -> string.  Remember to use your type system to help you in writing code.

You should try writing some functions with List.fold_left to get a feel for it.  It can be incredibly useful.

Tail recursion

A function is tail recursive if it calls itself recursively but does not perform any computation after the recursive call returns, but just immediately returns to its caller the value of its recursive call.  Tail recursive functions are more efficient than non-tail recursive functions for reasons that will be explained later in the course.  For now just observe the following difference between the sum and sum' functions above.  In the first sum function, after the recursive call returned its value, we add x to it.  In the tail recursive sum', after the recursive call returns, we immediately return the value without further computation.

Tail recursive functions tend to run faster than their standard counterparts.  Notice also that List.fold_left is tail recursive, whereas List.fold_right is not.  Typically, when given a choice between using the two functions, you should use List.fold_left for performance.  However, in some cases using List.fold_right is easier.  If you need to use List.fold_right on a very lengthy list, you may instead want to reverse the list first, and use List.fold_left.  So, we could have written map as

let map f l = List.fold_left (fun a x -> (f x) :: a) [] (List.rev l)

which would be tail recursive.