Level: Lib Thy Top: 2 1
Hypotheses:- f :


- n :

- i :
(n + 1) - f (n - i) = f n
- j :

- 0 < j
- j < (n - i) + 1
- MinAr(f;(j - 1) + i;n) = MinAr(f;j - 1;n - i) + i
- f (n - (j + i)) = f n
Conclusion:
j + i = MinAr(f;j;n - i) + i
Applied Tactic: RecCaseSplit `min_ar` THENA Auto'
Generated subgoals:1. j + i = j + i2. j + i = MinAr(f;j - 1;n - i) + i