Nuprl - Proof: iter via intseg split last 1

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At: iter via intseg split last 1

1. A : Type
2. f : A

A
3. u : A
4. a :

5. b :

6. e : {a..b

}

A
7. a<b

(Iter(f;u) i:{a..b

}. e(i)) = f((Iter(f;u) i:{a..b-1

}. e(i)),e(b-1))

By:	BackThru: Thm* f:(AAA), u:A, a,b:, e:({a..b}A). Thm* a<b Thm* Thm* (c:. Thm* (b = c+1 Thm* ( Thm* ((Iter(f;u) i:{a..b}. e(i)) = f((Iter(f;u) i:{a..c}. e(i)),e(c)))

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html