Nuprl - Proof: sub right less eq

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At: sub right less eq

m,n,x:

. nnsub(m;n)

n+x

By:	RewriteOfThm Thm* all Thm* (m:hnum. all(n:hnum. all(p:hnum. equal(le(sub(m,n),p),le(m,add(n,p)))))) (SimpsetC [`hol_to_nuprl`;`bequal`])

Generated subgoals:

None

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IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html