Nuprl - Proof: sub left sub

IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html
At: sub left sub

m,n,x:

. nnsub(m;nnsub(n;x)) = if n

x then m else nnsub(m+x;n) fi

By:	RewriteOfThm Thm* all Thm* (m:hnum. all Thm* (m:hnum. (n:hnum. all Thm* (m:hnum. (n:hnum. (p:hnum. equal Thm* (m:hnum. (n:hnum. (p:hnum. (sub(m,sub(n,p)) Thm* (m:hnum. (n:hnum. (p:hnum. ,cond(le(n,p),m,sub(add(m,p),n)))))) (SimpsetC [`hol_to_nuprl`;`bequal`])

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html