Nuprl - Proof: sub sub

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At: sub sub

b,c:

. c

(

. nnsub(a;nnsub(b;c)) = nnsub(a+c;b))

By:	RewriteOfThm Thm* all Thm* (b:hnum. all Thm* (b:hnum. (c:hnum. implies Thm* (b:hnum. (c:hnum. (le(c,b) Thm* (b:hnum. (c:hnum. ,all Thm* (b:hnum. (c:hnum. ,(a:hnum. equal(sub(a,sub(b,c)),sub(add(a,c),b)))))) (SimpsetC [`hol_to_nuprl`;`bequal`])

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html