Nuprl - Proof: less suc eq cor

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At: less suc eq cor

m,n:

. m<n &

m+1 = n

m+1<n

By:	RewriteOfThm Thm* all Thm* (m:hnum. all Thm* (m:hnum. (n:hnum. implies Thm* (m:hnum. (n:hnum. (and(lt(m,n),not(equal(suc(m),n))) Thm* (m:hnum. (n:hnum. ,lt(suc(m),n)))) (SimpsetC [`hol_to_nuprl`;`bequal`])

Generated subgoals:

None

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IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html