Nuprl - Proof: less sub add less

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At: less sub add less

n,m,i:

. i<nnsub(n;m)

i+m<n

By:	RewriteOfThm Thm* all Thm* (n:hnum. all Thm* (n:hnum. (m:hnum. all(i:hnum. implies(lt(i,sub(n,m)),lt(add(i,m),n))))) (SimpsetC [`hol_to_nuprl`;`bequal`])

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html