Nuprl - Proof: hsub less eq

IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html
At: hsub less eq

all(

n:hnum. all(

m:hnum. le(sub(n,m),n)))

By:	HOL "hsub_less_eq"

Generated subgoals:

None

About:

IF YOU CAN SEE THIS go to http://www.cs.cornell.edu/Info/People/sfa/Nuprl/Shared/Xindentation_hack_doc.html